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<h1><font color=#0000ff>Exponentiation</font></h1>
Time limit: 500 ms<br>
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<br>
<h2><font color=#0000ff>Problem</font></h2>
Problems involving the computation of exact values of very large magnitude and precision are common. For example, the computation of the national debt is a taxing experience for many computer systems. 

<br>
<br>This problem requires that you write a program to compute the exact value of R<sup>n</sup> where R is a real number ( 0.0 &lt; R &lt; 99.999 ) and n is an integer such that 0 &lt; n &lt;= 25.<br>
<h2><font color=#0000ff>Input Specification</font></h2>
The input will consist of a set of pairs of values for R and n. The R value will occupy columns 1 through 6, and the n value will be in columns 8 and 9.<br>
<h2><font color=#0000ff>Output Specification</font></h2>
The output will consist of one line for each line of input giving the exact value of R<sup>n</sup>. Leading zeros should be suppressed in the output. Insignificant trailing zeros must not be printed. Don't print the decimal point if the result is an integer.<br>
<h2><font color=#0000ff>Sample Input</font></h2>
<pre>95.123 12
0.4321 20
5.1234 15
6.7592  9
98.999 10
1.0100 12
</pre><br>
<h2><font color=#0000ff>Sample Output</font></h2>
<pre>548815620517731830194541.899025343415715973535967221869852721
.00000005148554641076956121994511276767154838481760200726351203835429763013462401
43992025569.928573701266488041146654993318703707511666295476720493953024
29448126.764121021618164430206909037173276672
90429072743629540498.107596019456651774561044010001
1.126825030131969720661201
</pre><br>
<h2><font color=#0000ff>Hint</font></h2>
If you don't know how to determine wheather encounted the end of input:

<br><i>s</i> is a string and <i>n</i> is an integer
<br><pre><b>C++</b>
<br>while(cin>>s>>n)
<br>{
<br>...
<br>}
<br><b>c</b>
<br>while(scanf("%s%d",s,&n)==2) //to  see if the scanf read in as many items as you want
<br>/*while(scanf(%s%d",s,&n)!=EOF) //this also work    */

<br>{
<br>...
<br>}</pre>
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